24x^2-72+48=0

Solution for 24x^2-72+48=0 equation:

24x^2-72+48=0

We add all the numbers together, and all the variables

24x^2-24=0

a = 24; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·24·(-24)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*24}=\frac{-48}{48}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*24}=\frac{48}{48}
=1
$